Question

in the given figure, interior angles of triangle abc are in the ratio of angle a : angle b = 3 : 2 and angle c is 30. find the measure of angle a , b and and angle dce

Answer 1

Answer:

In a △ABC, it is given that

∠A:∠B:∠C=3:2:1

It can also be written as

∠A=3x,∠B=2x and ∠C=x

We know that the sum of all the angles in triangle ABC is 180∘.

∠A+∠B+∠C=180∘

By substituting the values we get

3x+2x+x=180∘

By addition

6x=180∘

By division

x=180/6x=30∘

Now by substituting the value of x we get

∠A=3x=3(30∘)=90∘

∠B=2x=2(30∘)=60∘

∠C=x=30∘

We know that in the triangle ABC exterior angle is equal to the sum of two opposite interior angles

So we can write it as

∠ACE=∠A+∠B

By substituting the values we get

∠ACE=90∘+60∘

By addition

∠ACE=150∘

We know that ∠ACE can be written as ∠ACD+∠ECD

So we can write it as

∠ACE=∠ACD+∠ECD

By substituting the values we get

150∘=90∘+∠ECD

It is given that CD⊥AC so 

Answer 2

Answer:

360 degree when i solve this in rough copy