In the given figure, is a straight line. Find the value of . C 620 x 0 A O B
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Answered by
0
Answer:
friend figure is not attached
Step-by-step explanation:
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Answered by
3
Answer:
From the figure we know that ∠AOB is a straight line
So we get
∠AOB=180
o
It can also be written as
∠AOC+∠COD+∠BOD=180
o
By substituting the values
(3x−7)
o
+55
o
+(x+20)
o
=180
o
3x−7
o
+55
o
+x+20
o
=180
o
On further calculate
4x+180
o
=180
o
4x=112
o
x=28
o
By substituting the value of x we get
∠AOC=(3x−7)
o
=3(28
o
)−7
o
=84
o
−7
o
=77
o
∠BOD=(x+20)
o
=(28+20)
o
=48
o
Step-by-step explanation:
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