In the given figure , is the mid-point of . Prove that = .
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you are
Step-by-step explanation:
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Step-by-step explanation:
Let P(n) denote the statement 4 + 8 + … + 4n = 2n(n + 1) i.e., P(n) : 4 + 8 + 12 + … + 4n = 2n(n + 1)
Put n = 1,
P(1): LHS = 4
RHS = 2 (1)(1 + 1) = 4
P(1) is true.
Assume that P(n) is true for n = k
P(k): 4 + 8 + 12 + … + 4k = 2k(k + 1)
To prove P(k + 1)
i.e., to prove 4 + 8 + 12 + … + 4k + 4(k + 1) = 2(k + 1) (k + 1 + 1)
4 + 8 + 12 + … + 4k + (4k + 4) = 2(k + 1) (k + 2)
Consider, 4 + 8 + 12 + … + 4k + (4k + 4)
= 2k(k + 1) + (4k + 4)
= 2k(k + 1) + 4(k + 1)
= 2k2 + 2k + 4k + 4
= 2k2 + 6k + 4 = 2(k + 1)(k + 2) P(k + 1) is also true.
∴ By Mathematical Induction, P(n) for all value n ∈ N.
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