In the given figure, it is given that AE = AD and BD = CE. Prove that ΔAEB ≅ ΔADC.
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I hope it will help you for sure.
Step-by-step explanation:
Given - AE=AD, BD-CE
Prove - triangle AEB is congruent to triangle ADC
Proof - In triangle AEB and ADV
AE=AD (Given)
BD=BC(Given)
angle A is common
By SAS Congruence rule
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