In the given figure, it is given that ZABD = ZCDB ZPQB = 90°. If AB = x units, CD = y units and 1 1 1 PQ = z units, prove that 1/x+1/y=1/z
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In ΔABD and ΔPQD
∠D= ∠D (common)
∠BAD=∠QPD (corresponding angles)
So, ΔABD∼ΔPQD (by AA similarity criterion)
⇒PQAB=QDBD (Ratio of corresponding sides of two similar triangles)
⇒zx=QDBQ+QD
⇒zx=QDBQ+1
zx−1=QDBQ
⇒zx−z=QDBQ ---(i)
Similarly in ΔCBD and ΔPBQ
∠B=∠B (common)
∠BCD=∠BPQ (corresponding angles)
So,ΔCBD∼ΔPBQ (by AA similarity criterion)
⇒PQCD=BQBD (Ratio of corresponding sides of two similar triangles)
⇒zy=
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