Question

In the given figure: (iv) ; AB = AC, BD perpendicular to AC, CE perpendicular to AB. Prove that BD = CE.

Answer 1

AB = AC     (given)

BD is perpendicular to AB    (given)

CE is perpendicular to AB   (given)

To be proof :

BD = CE

In ΔADB and ΔAEC

∠EAD = ∠EAD   (given)

∠ADB = ∠AEC   (each 90°)

AB = AC          (given)

Hence,

by AAS(Angle-Angle-Side) congruence condition the ΔADB ≅ ΔAEC

Therefore,

BD = CE        [ by CPCT ]

Answer 2

Answer:

Step-by-step explanation:

Angle bdc and angle Feb are right angle and e and d are middle points of ab and AC means CB is equal to DC and BC is common by the application if two triangle has 2 sides equal and 1 angle equal means triangles are

congruent that's why bd=ce