Question

In the given figure, KT bisects ∠ IKE and ∠ ITE. Prove that ΔKIT =ΔKET.
there is my assignment its q5

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Answer 1

Answer:

(i)

∠DAC=∠BAC

∠DCA=∠BCA

AC=AC

(ii)

By ASA criterion, triangles are congruent.

(iii)

Since triangles are congruent hence, AB=AD because both sides originate from equal angles in two triangles.

(iv)

Since triangles are congruent hence,CD=CB because both sides originate from equal angles in two triangles.

Answer 2

Answer:

Hello

Step-by-step explanation:

Given : , KT bisects ∠ IKE and ∠ ITE,

          ∴ angle IKT = angle EKT --------- i

          ∴ angle ITK = angle ETK --------- ii

To Prove : ∆KIT≅ ∆KET

Solution : In ∆KIT and ∆KET,

               angle IKT = angle EKT (from i)

               KT = TK (common side)

               angle ITK = angle ETK (from ii)            

Hence , ∆KIT≅ ∆KET by Angle - Side -Angle criteria of congruency.

Hence proved :)