In the given figure, l is parallel to m. Prove that angle 1 + angle 2 - angle 3 = 180°
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Given: l || m
RTP : angle 1 + angle 2 - angle 3 = 180 degree
Construction: Extend BC and let it intersect line 'm' at point 'F'. Let the angle BFD be 4.
proof: now,
angle 1 +angle 4 = 180 degree (co-int pair)
or angle 4= 180 - angle 1 -----(1)
IN triangle BCF ,
angle 3 + angle 4 = angle 2 (Exterior angle )
Applying equation 1, we have
angle 3 + 180- angle 1 =angle 2
or angle 1 + angle 2 -angle 3 = 180 (proved)
Kyra0809:
Thanks a lot! ^_^
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