In the given figure, l || m and a transversal t cuts them. If ∠7 = 80°, find the measure of each of the remaining marked angles.
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➝It is given that ∠7 = 80o From the figure we know that ∠7 and ∠8 form a linear pair of angles So it can be written as ∠7 + ∠8 = 180°
By substituting the values 80° + ∠8 = 180
➝ On further calculation ∠8 = 180o – 80o By subtraction ∠8 = 100°
☞ From the figure we know that ∠7 and ∠5 are vertically opposite angles So we get ∠7 = ∠5 = 80°
➝ From the figure we know that ∠6 and ∠8 are vertically opposite angles So we get ∠6 = ∠8 = 100°
➝ It is given that, l || m and t is a transversal So the corresponding angles according to the figure is written as
∠1 = ∠5 = 80°
∠2 = ∠6 = 100°
∠3 = ∠7 = 80°
∠4 = ∠8 = 100°
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