Question

in the given figure l || m, the measure OY Y

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Answer 1

Answer:

Let x=5a and y=4a

Now ∠y+∠1=180

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(Angle made on straight line (n) are supplementary)

⇒4a+∠1=180

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⇒∠1=180

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−4a..........(i)

Now m∣∣n and t is transversal

∴∠x=∠1 (Corresponding angles)

⇒5a=∠1

⇒5a=180

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−4a

⇒9a=180

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⇒a=20

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Now ∠y=4a=4×20

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=80

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Now l∣∣n and t is transversal.

∴∠z=∠y (Alternate angles)

⇒∠z=80

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solution