Question

In the given figure, LCAB = 500 and L CBD = 300.
Calculate LDAC, LDCB, LCDB.

Answer 1

Answer:

angle (DAC)= angle(DBC) = 30° {Angles in the same segment are equal}

Since ABCD is cyclic quadrilateral.

Therefore, angle(DAB) + angle(DCB)=180° {Opp. angles in a cyclic quadrilateral are supplementary}

30° + 50° + angle(DCB)=180°

angle(DCB)=180°-80°

angle(DCB)=100°

In ️ DCB,

angle(DCB)+angle(DBC)+angle(CDB)=180° {Angle Sum Property of a ️ }

100°+30°+angle(CDB)=180°

angle(CDB)=180°-130°

angle(CDB)=50°