Question

In the given figure, LCPD = LBPD and AD is the bisector of ZBAC . Prove that ACAP ​

Answer 1

Answer:

For triangles CAP and BAP,

AP = PA (common side)

∠ BAP = ∠ CAP (AD is the angle bisector of ∠ BAC)

→ ∠ BPA = ∠ CPA (as we have given ∠ BPD = ∠ CPD, ∠ BPA = 180⁰ - ∠ BPD and ∠ CPA = 180⁰ - ∠ CPD)

Hence Δ CAP congruent to Δ BAP

CP = BP (CPCT).