Question

In the given figure, length of the object AB = 9 cm. Find the nature and position of the final image and also its length. Assume that each lens is a
thin lens.
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Answer 1

HEYA GM ❤

SEE THE ATTACHMENT.....

TQ ❤ ❤

Answer 2

Answer:

position = 4.8 cm and nature= real and diminished and between c and f

Explanation:

the total power of the lens will become 24.99

p=1/f

f=1/p

f=1/24.99

f=100/2499

f=0.04 m

on converting to cm, we get that f = 4 cm

by using lens formula, we get

1/v -1/u = 1/f

1/v= 1/4- 1/24 ---------(here its -1/24 because of sign convention )

1/v= 6-1/24

v= 24/5

v= 4.8 - ------------------------------------------------------------------------  (1)

now putting it in magnification formula, we get

m=hi/ho

m= v/u

hi/ho=v/u

hi=v* ho/u

hi = 4.8 * 9/24

hi=0.2* 9

hi=1.8 ----------------------------------------------------------------------------  (2)