Question

In the given figure, line l is the bisector of an angle _A and B is any point on l. If BP and BQ are perpendiculars from B to the arms of Q L B ZA, show that (i) AAPB = AAQB A Р (ii) BP = BQ, i.e., B is equidistant from the = arms of ZA.​

Answer 1

Answer:

In △APB and △AQB

∠APB=∠AQB (Each 90

o

)

∠PAB=∠QAB (l is the angle bisector of ∠A)

AB=AB (Common)

∴△APB≅△AQB (By AAS congruence rule)

∴BP=BQ (By CPCT)

It can be said that B is equidistant from the arms of ∠A.