in the given figure line l meets x-axis at A and y-axis at B.if equation of is x+y-3=0 and PA:PB=2:3,then cords of p are
Answers
Given : line x+y-3=0 meets x-axis at A and y-axis at B.
PA : PB = 2 : 3
To Find : Coordinates of P
Solution:
x+y-3=0 meets x-axis at A and y-axis at B.
at x axis y = 0
=> x + 0 - 3 = 0 => x = 3
A = ( 3 , 0)
at y axis x = 0
=> 0 + y - 3 = 0 => y = 3
B = ( 0 , 3)
A = (3 , 0) , B = ( 0 ,3 )
PA : PB = 2 : 3
=> P = ( 2 * 0 + 3 * 3)/(2 + 3) , ( 2 * 3 + 3 * 0)/(2 + 3)
= 9/5 , 6/5
Coordinates of P are ( 9/5 , 6/5)
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Answer:
= 9/5 , 6/5
Step-by-step explanation:
Given : line x+y-3=0 meets x-axis at A and y-axis at B.
PA : PB = 2 : 3
To Find : Coordinates of P
Solution:
x+y-3=0 meets x-axis at A and y-axis at B.
at x axis y = 0
=> x + 0 - 3 = 0 => x = 3
A = ( 3 , 0)
at y axis x = 0
=> 0 + y - 3 = 0 => y = 3
B = ( 0 , 3)
A = (3 , 0) , B = ( 0 ,3 )
PA : PB = 2 : 3
=> P = ( 2 * 0 + 3 * 3)/(2 + 3) , ( 2 * 3 + 3 * 0)/(2 + 3)
= 9/5 , 6/5
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