Question

In the given figure, line segments AB and

CD intersect each other at the point O such

that AO = OD and OB = OC prove that

△AOC is congruent to △BOD

Answer 1

In triangles AOC and BOD, we have,

AO = BO, (O, the midpoint of AB)

∠AOC = ∠BOD, (vertically opposite angles)

CO = OD, (O, the midpoint of CD)

So, by SAS congruence we have,

∆AOC ≅ ∆BOD

Hence Proved

Hope it is helpful for u....

If yes then plz mark it as brainliest......

Answer 2

Answer:

Step-by-step explanation:

In triangles AOC and BOD, we have,

AO = BO, (O, the midpoint of AB)

∠AOC = ∠BOD, (vertically opposite angles)

CO = OD, (O, the midpoint of CD)

So, by SAS congruence we have,

∆AOC ≅ ∆BOD