Question

in the given figure lines AB and CD intersect at O. if angle BOC+angle BOE=70° and angle BOD=130°. find angle BOE and reflex angle AOC​

Answer 1

Step-by-step explanation:

BOD + BOC =180

130 + BOC = 180

BOC = 180-130

BOC =50

BOC + BOE = 70

50 + BOE =70

BOE =70-50

BOE = 20

AOC + BOD =180

AOC + 130 = 180

AOC = 50

reflex of AOC

=360-50

=310

hope this answer will help u

Answer 2

Question :-

In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

Answer :-

Since AB is a straight line,

∴ ∠AOC + ∠COE + ∠EOB = 180°

or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]

or ∠COE = 180° – 70° = 110°

∴ Reflex ∠COE = 360° – 110° = 250°

Also, AB and CD intersect at O.

∴∠COA = ∠BOD [Vertically opposite angles]

But ∠BOD = 40° [Given]

∴ ∠COA = 40°

Also, ∠AOC + ∠BOE = 70°

∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°

Thus, ∠BOE = 30° and reflex ∠COE = 250°.

Plz mrk as brainliest ❤