In the given figure, lines
AB and CD intersect at
O. If AOC + 2 BOE = 70°
and BOD = 40°, find
BOE and reflex 2 COE.
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Answer:
Solution:
From the given figure, we can see;
∠AOC, ∠BOE, ∠COE and ∠COE, ∠BOD, ∠BOE form a straight line each.
So, ∠AOC + ∠BOE +∠COE = ∠COE +∠BOD + ∠BOE = 180°
Now, by substituting the values of ∠AOC + ∠BOE = 70° and ∠BOD = 40° we get:
70° +∠COE = 180°
∠COE = 110°
Similarly,
110° + 40° + ∠BOE = 180°
∠BOE = 30°
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