Question

in the given figure lines ab , Cd and ef intersect at o find the measure of angle AOC and angle COF
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Answer 1

Answer:

<AOC =<bod =35 (V.O.A)

<AOE=<BOF=40

NOW,

AOC+BOF+COF=180(LINEAR PAIR )

35+40+COF=180

75+COF=180

COF=180-75

=105 ANSWER.....

Answer 2

$\huge\underline\mathfrak\red{Answer:}$

From the figure,

• $\angle$BOF = $\angle$AOE
• $\angle$BOF = 40°
• $\angle$AOC = $\angle$BOD
• $\angle$AOC = 35°.

1. [vertically opposite $\angle$s]
2. [Given $\angle$AOE = 40°]
3. [Vertically opposite $\angle$s]
4. [given $\angle$BOD = 35°]

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Clearly, $\angle$AOC + $\angle$COF + $\angle$BOF = 180°

35° + $\angle$COF + 40° = 180°

$\angle$COF + 75° = 180°

$\angle$COF = 180°-75°

$\angle$COF = 105°.

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