Question

In the given figure, lines CA and CB,touch the circle with centre D in A andB. If < ADB = 125° then
i. Find the measure of <ACB
ii. Find the type of the quadrilateral
ABCD
​

Answer 1

Answer:

62'5

Step-by-step explanation:

angle ACB is twice of 125

because (10.8) thereon

so.

2<ACB=125

<ACB=125/2= 62.5 degree

Answer 2

Answer:

Step-by-step explanation:

I) 55° (I think)

II) ABCD is a Diamond