Question

in the given figure lm||ab al=x-3 ac=2x bm=x-2 and bc=2x+3 find the value of x​

Answer 1

$\Large{\red{\underline{\underline{\tt{AnSweR:}}}}}$

Here LM ║ AB .

AC = AL+ LC                     BC = BM + MC

LC = 2x-(x-3) = x+3           MC = 2x+3-(x-2) = x+5

AL/LC      =   BM/MC

(x-3)/(x+3)  =  (x-2)/(x+5)

(x-3)(x+5)   =  (x-2)(x+3)

 x²+2x-15    =  x²+x-6

 2x-x            =  15-6

  x  =  9

Answer 2

AnSweR:

Here LM ║ AB .

AC = AL+ LC BC = BM + MC

LC = 2x-(x-3) = x+3 MC = 2x+3-(x-2) = x+5

AL/LC = BM/MC

(x-3)/(x+3) = (x-2)/(x+5)

(x-3)(x+5) = (x-2)(x+3)

x²+2x-15 = x²+x-6

2x-x = 15-6

x = 9