In the given figure, LM AB . If AL = x – 3, AC = 2x, BM = x – 2 and BC = 2x + 3. Find the value
of x.
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Step-by-step explanation:
In triangle ABC
LM ll AB
By basic proportionality theorem (i.e. B.P.T.)
CL/LA = CM/MB
By using 'componendo property'
CL+LA / LA = CM+MB/MB
CA/LA = BC/MB.... (C-L-A) & (C-M-B)
..... (1)
Putting value in equation (1)
2x/x-3 = 2x+3/x-2
2x(x-2)=(2x+3)(x-3)
2x^2-4x = 2x^2 -6x +3x.-9
Cancel the same terms on both sides
-4x = - 6x+3x-9
-4x = - 3x - 9
-4x + 3x = - 9
-x = - 9
i. e. X= 9
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