Question

In the given figure, LM || CB and LN || CD.
Prove that AM/AB=AN/AD​

Answer 1

Answer:

Step-by-step explanation:

In triangle ALM, since LM║CB,

AB/AM=AC/AL(Converse of BPT) (1)

Similarly, in triangle ALN,since LN║CD,

AD/AN=AC/AL(Converse of BPT) (2)

from (1) and (2),

AB/AM=AD/AN

On reversing, we get,AM/AB=AN/AD..

Answer 2

In the given figure, we can see, LM || CB,

By using basic proportionality theorem, we get,

AM/MB = AL/LC …..(i)

Similarly, given, LN || CD and using basic proportionality theorem,

∴ AN/AD = AL/LC ……(ii)

From equation (i) and (ii), we get,

AM/MB = AN/AD

Hence, proved.