Question

In the given figure, LM||CB and LN|| CD.

Prove that $\frac{AM}{AB}$=$\frac{AN}{AD}$

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Answer 1

In ∆ABC,

LM || BC

By proportionality theorem ,

$\frac{am}{ab} = \frac{a l}{ac}$

....... (1)

similarly ,

In ∆ADC,

LN || CD

By proportionality theorem,

$\frac{an}{ad} = \frac{al}{ac}$

........ (2)

From (1) and (2) ,

$\frac{am}{ad} = \frac{an}{ad}$

I hope it helps you.....

Answer 2

Answer:

In ∆ABC,

LM || BC

By proportionality theorem ,

ab/am = ac/al

....... (1)

similarly ,

In ∆ADC,

LN || CD

By proportionality theorem,

ad/an = ac/al

........ (2)

From (1) and (2)

ad/am = ad/an

I hope it helps you...