Question

in the given figure, LM parallel to CB and LN parallel to CD. Prove that AM/AB=AN/AD
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Answer 1

Answer:

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Answer 2

Answer:

In triangle ABC, LM parallel to CB (given)

.°. AM / AB = AL / AC ...(1) (cor. to B.P.T.)

In triangle ADC, LN parallel to CD (given)

.°. AN / AD = AL / AC ...(2) (cor. to B.P.T.)

From (1) and (2), we get

AM / AB = AN / AD, as required.