In the given figure, <A = <C and AB = BC. Show that ∆ ABD = ∆ CBE
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in ∆ ABD and ∆ CBE
<A = <C [ given ]
AB = BC [ Given ]
B = B [ common angle ]
hence ASA congruent rule ∆ ABD≈ ∆ CBE
therefore ∆ ABD = ∆ CBE [ by cpct ]
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