Math, asked by Anonymous, 1 year ago

IN THE GIVEN FIGURE <ABC=30°,<EDF=(40-X)° AND <ADE = (13X+20) . SHOW THAT BC PARALLEL TO DE
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Answered by Anonymous
11
hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝









Given : <ABC= 30, <EDF= (40-x) degree and <ADE= (13x+20)
To prove : BC is parallel to DE
Proof:
<ABC+ <  DBC = 180 (Linear pair axiom)
30 + <DBC= 180
< DBC = 180-30
            = 150 degrees
also, < ADE + < EDF = 180 (Linear pair axiom)
          (13x+20)+(40-x) = 180
                       12x +60  =  180
                      12x = 180 - 60 
                        12x = 120
                         x = 120/12 = 10
                        x = 10
Now substitute the value of x in both the terms ...
<ADE = 13x+20 : where x = 10                <EDF = 40-x
13*10+20 = 150 degrees    &   40-10 = 30 degrees...
As seen above ,
< DBC = < ADE (Alternate angles are equal)
Hence, we can say that - BC is parallel to DE




that's all
Answered by VarunJogi428
1

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