Question

in the given figure<ABC=65°,<BCE=30°,<Dce=35°and<cef=145° prove that AB||EF​

Answer 1

Answer :

<bce + <ecd = <c

30°+35°=<c

65°=<c

<b=<c (alternate angles )

65°=65°

so , ab||cd

<ecd + <e = 180° (co-interior angles)

35°+ 145° = 180°

180°=180°

so , cd||ef

now , ab||cd

cd||ef

so , ab||ef