Question

in the given figure,<abc=90°

find CD

Answer 1

Given ∠ABC=90°,BD is perpendicular to AC, BD=8,and, AD=4, as shown in the diagram.

Let ∠ACB=x,⇒∠CBD=90−x

⇒∠ABD=x,⇒∠BAD=90−x

⇒ΔABC,ΔADB,andΔBDC are similar

⇒BD/CD=AD/DB

⇒8/CD=4/8

⇒CD=8×8/4=16

Answer 2

Answer:

Let ∠ACB=x,  ∠CBD=90−x

∠ABD=x,   ∠BAD=90−x

ΔABC,ΔADB,andΔBDC are similar

BD/CD=AD/DB

8/CD=4/8

CD=8×8/4=16 cm ------------------------- Answer