Question

In the given figure, <ABE=15°, <ABD = 80° and <EBC=75°. Find angle DBC​

Answer 1

Step-by-step explanation: In the figure,

Angle ABE = 15°

Angle ABD = 80°

So, Angle EBD = 80° -15°

Angle EBD = 65°

We know that Angle EBC = 75°

EBC EBD = DBC

75° -65° = DBC

Therefore, Angle DBC is 10°

Answer 2

$\small\bf\underline\purple{In \: the \: Figure}$

• Angle ABE = 15⁰
• Angle ABD = 80⁰

$\small\bf\underline\green{So \: for \: finding \: (EBD)}$

• EBD = 80⁰ - 15

So Now angle EBD is 65⁰

$\small\bf\underline\green{So \: we \: Know \: That \: (EBC) = 75⁰}$

• Because it is given in question

$\small\bf\underline\green{EBC \: - \: EBD}$

• Value of EBC =75⁰ AND EBD =65⁰
• Then By subtracting them we get DBC

$\small\bf\underline\pink{DBC \: = \: 10⁰ }$