Question

In the given figure <B =90° <A=<C and BC=10cm ,Then find the value of tan45°​

Answer 1

Answer:

Let the Height of the Tree =AB+AD

and given that BD=8 m

Now, when it breaks a part of it will remain perpendicular to the ground (AB) and remaining part (AD) will make an angle of 30

o

Now, in △ABD

cos30

o

=

AD

BD

⇒BD=

2

3

AD

⇒AD=

3

2×8

also, in the same Triangle

tan30

o

=

BD

AB

⇒AB=

3

8

∴ Height of tree =AB+AD=(

3

16

+

3

8

)m=

3

24

m=8

3

m

Answer 2

Explanation:

In that given figure,

angle B = 90°

angle A = angle C = 180° - 90° / 2 = 45°

BC = 10 cm

If angle A = angle C, then BC = BA = 10 cm

tan 45° = BA / BC = 10 / 10 = 1

Answer:

The value of tan 45° is 1.