Question

in the given figure <POC and <QOC form a linear pair <POC=<QOE=135° and <COD=<EOD.Find the measures of <POE,<EOC, and <DOC.​

Answer 1

Answer:

<POC=135°[given]

<POC +<QOC=180°[linear pair]

135°+<QOC=180°

<QOC=180°-135°

=45°

now <QOE=135°(given)

<QOE=<EOC++<QOC

<EOC=<QOE-<QOC

=135°-45°

=90°

<EOD=<DOC

<EOD+<DOC=90°

2(<DOC) =90°

<DOC=90°/2

=45°

now

<POE+<QOE=180°(linear pair)

<POE+135°=180°

<POE=180°-135°

<POE=45°

Step-by-step explanation:

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Answer 2

Answer:

answer of the question set by step