In the given figure, m ∠BCD = 70°, m ∠BPD = 110° . Observe the following figure and answer the questions *.
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Answer:
Given:∠BOD=40
∘
Since AB and CD intersects, ∠AOC=∠BOD(vertically opposite angles)
∠AOC=40
∘
Also,∠AOC+∠BOE=70
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⇒∠BOE=70
∘
−∠AOC=70
∘
−40
∘
=30
∘
We need to find reflex∠COE
Reflex∠COE=360
∘
−∠COE
Now, ∠AOC+∠COE+∠BOE=180
∘
⇒∠COE+(∠AOC+∠BOE)=180
∘
⇒∠COE+(40
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+30
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)=180
∘
⇒∠COE=180
∘
−70
∘
=110
∘
Reflex∠COE=360 −110
=250
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