In the given figure, M is the centre of the circle, seg AD = seg AC Prove that seg AB is the bisector of angle DAC. (write only proof)
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Step-by-step explanation:
If. AD = AC
1/2 AD = 1/2 AC
AP = AQ
In ∆ APM & ∆ AQM,
Ang. APM = Ang. AQM
AM = AM
AP = AQ
Hence, ∆APM is congruent to ∆AQM
So, ang. PAM = ang. QAM
Hence it is proved that, seg AB is the bisector of angle DAC.
Hope it helps...
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Answered by
0
Answer:
Step-by-step explanation:
If. AD = AC
1/2 AD = 1/2 AC
AP = AQ
In ∆ APM & ∆ AQM,
Ang. APM = Ang. AQM
AM = AM
AP = AQ
Hence, ∆APM is congruent to ∆AQM
So, ang. PAM = ang. QAM
Hence it is proved that, seg AB is the bisector of angle DAC.
Hope it helps...
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