In the given figure , M is the midpoint of side CD of a parallelogram ABCD . The line BM is drawn intersecting AC at L and AD produced at E . Proved that EL = 2BL
Answers
Answered by
1069
See diagram.
ΔBCM & ΔEDM are similar. MD=CM => BC = DE, as AD = BC, AE = 2 BC
ΔACL & ΔAEL are similar. EL / BL = AE / BC = 2
So EL = 2 BL
ΔBCM & ΔEDM are similar. MD=CM => BC = DE, as AD = BC, AE = 2 BC
ΔACL & ΔAEL are similar. EL / BL = AE / BC = 2
So EL = 2 BL
Attachments:
Answered by
145
Step-by-step explanation:
hey this is ur answer, may this answer help u
Attachments:
Similar questions