In the given figure | || m ll n.
Find the value of x, y and z.
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Answered by
15
Answer:
z+10=3x-60......corresponding angles
3x-z=10+60
3x-z=70.....(1)
3x-60=x+20....alternate angles
3x-x=20+60
2x=80
x=80/2
x=40
put x=40in (1)
3x-z=70
3*40-z=70
120-z=70
z=120-70=50
z=50
y+3x-60=180.....angle in linear pair
y+3*40-60=180
y+120-60=180
y=180-60=120
y=120
hence x=40,y=120,z=50.
Answered by
1
Answer:
z + 10 = 3x - 60 corresponding angles
3x - z = 10 + 60
3x - z =70....(1)
3x - 60 = x + 20 ....alternate angles
3x - x = 20 + 60
2x = 80
x = 80/2
x = 40
put x=40in (1)
3x - z = 70
3^ * 40 - z = 70
120 - z = 70
z = 120 - 70 = 50
z=50
v + 3x - 60 = 180 .....angle in linear pair
y+3^ * 40 - 60 = 180y + 120 - 60 = 180
y = 180 - 60 = 120
y = 120
hence x = 40, y = 120, z = 50
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