Question

In the given figure (not drawn to scale), ABCD is a
parallelogram, one of whose side is 5 cm. Find the
area of APCD, if P lies on the line AB where O is
the centre of the outer circle with radius 6.5 cm.​

Answer 1

Answer:

Here is your answer

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Step-by-step explanation:

Given :

DC = AB = 8

AD = CB = 6

Let us first find the diagonal AC by pythagoras theorem :

H = P2 + B2

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Vp? + 62

h = V82 + 62 =

V64 + 36

h = v100

h = 10 =

Since AC = the diameter of the the circle then,

RE

R =

10

R = 5

.The Area of the circle =

T p2

=> 3.14 x 5 x 5

=) 78.5

•Area of Rectangle = Length x Breadth

=> 8x6

=> 48

= The area of Shaded region = Area of Circle - Area of Rectangle

=) 78.5

Area of Rectangle = Length x Breadth

=> 8x6

=> 48

The area of Shaded region Area of Circle - A of Patangle

=> 78.5 - 48

=> 30.5 Ans