In the given figure (not drawn to scale), ABCD is a square such that AE = DE. Find ZBEC A E D 12. 287 (A) 28° (B) 56° (C) 62° (D) 24°
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Answer:
hence option B is correct
Step-by-step explanation:
Correct option is
B
56
0
from square ABCD , AE=ED
hence BE=EC hence <EBC=<ECB ( two sides of triangle is equal then opposite two angles are equal.)
now<EBC=(90
0
−<ABE)=(90
0
−28
0
)=62
0
<EBC=<ECB=62
0
now <BEC=180
0
−(<EBC+<ECB)=180
0
−62
0
−62
0
=56
0
hence option B is correct.
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