In the given figure (not drawn to scale), OABC is a quadrilateral with ABC on horizontal ground and O is vertically above A. M is the mid-point of BC. If ∠BAC = 90°, AB = AC = 16 cm and OA = 12 cm, calculate the length of OB.
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angle BAC + angle AOC = 180
so
BAO is a straight line
BAO = OB = 12 +16 = 28cm
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