Question

In the given figure, O is a point in the interior of a triangle ABC, OD ⊥ BC, OE ⊥ AC and OF ⊥ AB. Show that
(i) OA^2+ OB^2 + OC^2– OD^2 – OE^2– OF^2 = AF^2 + BD^2 + CE^2,
(ii) AF^2+ BD^2+ CE^2= AE^2 + CD^2 + BF^2.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

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Step-by-step explanation:

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