Question

In the given figure, O is the center of a circle. If ∠OAB = 40° and C is a point on the circle, then find ∠ACB​

Answer 1

Answer:

ANSWER

∵OA=OB (radius of circle)

∴∠OAB=∠OBA (angles opposite to equal sites)

∠OBA=40

0

In right angled ΔOAB

∠OAB+∠OBA+∠AOB=180

0

40

0

+40

0

+∠AOB=180

0

∠AOB=180

0

–80

0

∠AOB=100

0

We know that

∠ACB=

2

1

∠AOB

= 2/1 ×100⁰=50⁰