Question

in the given figure o is the center of the circle.
acb=60 then find oab ​

Answer 1

Answer:

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Step-by-step explanation:

so here in the adjoining circle with centre O

angle acb intercepts arc ab on circumference of circle

thus by inscribed angle theorem

we get

angle acb=1/×m(arc ab)

ie m(arc ab)=60×2=120 degrees

so here ao and ob are two required radii of given circle

thus ao=ob (radii of same circle)

hence triangle aob is an isoceles triangle

so this angle oab=angle oba (1)

now here angle aob is a central angle

so we know that

measure of central angle is same as that of arc intercepted by the central angle ie arc subtended by central angle on circumference of circle

hence angle aob=m(arc ab)=120 degrees

so by applying angle sum property on triangle aob

we get

angle aob+angle oab+angle oba=180

ie angle oab+angle oab=180-120

ie 2.angle oab=60

ie angle oab=30 degrees

thus option 1 is ryt

Answer 2

Answer:

Answer is very simple. it's 60.

Step-by-step explanation:

B+60° = 180°

B= 180°- 60° = 60°. Same goes to A

A+60+ 60= 180

A+ 120= 180

A= 180- 120 = 60 °

A= 60, B= 60.