Question

in the given figure ,o is the center of the circle and ab=ac if abd=40 degree, find box and bdc​

Answer 1

Answer: BA=AC

∠ABC=50

∘

Since BA = AC

∠ABC=∠ACB=50

∘

so ∠A=180

∘

−(50

∘

+50

∘

)

=80

∘

We know ∠BOC=2(∠BAC)

∠BOC=2×80=160

∘

ABCD is a cyclic Quadrilateral

So ∠A+∠D=180

∘

80

∘

+∠D=180

∘

⇒∠BDC=100

∘

Step-by-step explanation:

Answer 2

Answer:

BA=AC

∠ABC=50 ∘

Since BA = AC

∠ABC=∠ACB=50 ∘

So, ∠A=180 ∘

−(50 ∘ +50 ∘ )=80 ∘

We know ∠BOC=2(∠BAC)

∠BOC=2×80=160

∘

ABCD is a cyclic Quadrilateral

So ∠A+∠D=180 ∘

80 ∘ +∠D=180 ∘ ⇒∠BDC=100 ∘.

$thanks$