Question

In the given figure " o " is the center of the circle and AB, CD are equal chords. If angle AOB = 70 degrees . Find the angle of the triangle OCD.

please answer this question with step - by- step explanation. ​

Answer 1

Answer:

In triAOB and TriCOD

AB=CD(given)

AO=DO(radii of the circle)

BO=CO(radii of the circle)

therefore, tri AOB congruent to triCOD

angleAOB=angleCOD=70 degree (CPCT)

In triCOD,

angleCOD=70 and

angleOCD=ODC(angle opp to each other)–(a)

therefore,

angleCOD +angle OCD +angleODC=180.(angle. sum property of triangle)

70+ 2angleOCD=180 –from (a)

2angleOCD=180–70

OCD=110/2 =55 degree

Since,angleOCD=ODC=55 degree.

Answer 2

ur answer in attachment..

hope it's helps u..

thank u!!