Question

In the given figure , O is the center of the circle. AOB =110°
find m(arc AMB )​

Answer 1

Answer:

m(arcAMB) = 121/63 r

circumference of sector of circle = theta°/

360°×2πr

= 110/360× 2πr= 110/360×2×22/7×r

= 121/63 r

Answer 2

Given:

∠AOB=110°

To find:

m(arc AMB).

Solution:

We know that,

circumference of a sector of a circle$=\frac{\alpha }{360}$×$2\pi r$

Therefore, putting the values in the above equation we get,

m(arc AMB)=$\frac{110}{360}$×$2$×$\frac{22}{7}$×$r$

=$\frac{121}{63}r$

Hence, m(arc AMB) is$\frac{121}{63}r$.