in the given figure o is the center of the circle. if angle AOB=60° find the measure of angle AOC and angle ABC
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angle AOB+angleAOC=180(sum of all angle in a stright line is 180)
angleAOC=180–60
angle AOC=120
in this question angle BAC= 90 digree because the angle in circamference of half circle should be 90 digree.
sides AO,OB&OC are equal because these are the radious of circle.
angle OAB&OBA are equal(OB=OA),now in tringle AOB
let angle ABO=x=angle ABC,
angle ABO=angle BAO
x+x+angleAOB=180 (sum all angle in tringle is 180)
2x=180–60
x=60 digree=angle ABC
HOPE IT’S HELP YOU
angleAOC=180–60
angle AOC=120
in this question angle BAC= 90 digree because the angle in circamference of half circle should be 90 digree.
sides AO,OB&OC are equal because these are the radious of circle.
angle OAB&OBA are equal(OB=OA),now in tringle AOB
let angle ABO=x=angle ABC,
angle ABO=angle BAO
x+x+angleAOB=180 (sum all angle in tringle is 180)
2x=180–60
x=60 digree=angle ABC
HOPE IT’S HELP YOU
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