Question

in the given figure, O is the center of the circle. If BOC=120, then find the value of x.

Answer 1

this is your answer

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Answer 2

Answer:

ABCD is a cyclic quadrilateral. we have 

∠ABC+∠ADC=180o 

∠ABC=180o−120o=60o 

Also  ∠ACB=90o   ( angle on a semi circle ) 

In ΔABC we have 

∠BAC+∠ACB+∠ABC=180o  

∠BAC+90o+60o=180o 

∠BAC=180o−150o=30o