Question

in the given figure o is the center on circle ab is chord in aob show that angleoab=angle oba

Answer 1

In the given figure-- join oa and ob
. Then ; in triangle oab ab = oa ( radii of a circle) so angle oab = angle oba ... because it isosceles triangle

Answer 2

Heya..
Here's ur required answer....
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A chord AB is drawn and the points A and B are connected to centre O.

Now,
draw a perpendicular to the Centre 0 from the middle of the chord AB at point D

Now,
In traingle OAD and OBD,

OA = OB [since radius of circle]

Angle AOD = Angle BOD

Angle ODA = Angle ODB [ since right angle.]

So.. Triangle AOD ≈ Traingle BOD.

So, angle OAD = angle OBD.

Since angle OAD = angle OAB and angle OBD= angle OBA.

So..
We can say, angle OAB=angle OBA._[Proved]

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Hope u got it.

Proud to help you.