in the given figure o is the centre of a cercle such that OA=5 cm, AB=8 cm and OD is perpendicular to AB, then find the length of CD
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In Fig 10.3 if OA = 5 cm, AB = 8 cm and OD is perpendicular to AB then CD is equal to
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OC is perpendicular on chord AB OC bisects the chord AB AC = CB Now, AC + CB = AB AC + CB = 8 AC = 8/2 4 cm OCA is a right angled triangle AO^2 = AC^2 ... More
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