Question

In the given figure, O is the centre of a circle, AB is a diameter and AC
a chord. Prove that AB > AC.​

Answer 1

Answer:

ABis greater than AC

the distance of AB

is more than

the distance of AC

Answer 2

Answer:

In triangle AOC,

AO+OC>AC [sum of two sides of a triangle is greater than the third side]

BUT,AO=OC=OB= radius of the circle

THEREFORE,→AO+OC>AC

→ AO+OB>AC

→ AB>AC

Hence proved